function solution3(arr, divisor) {
answer = arr.filter((i) => i % divisor === 0).sort((a, b) => a - b);
// divisor가 0인 것만
}
return answer.length === 0 ? [-1] : answer;Level
프로그래머스 Lv1
Recruitment
function solution3(arr, divisor) {
answer = arr.filter((i) => i % divisor === 0).sort((a, b) => a - b);
// divisor가 0인 것만
}
return answer.length === 0 ? [-1] : answer;